Code archives/Algorithms/Conversion Log Date
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| This is kinda like the Startrek Stardate. Useful for telling people certain dates in secrecy. I know its kinda stupid, but its fun because people always want to know the day, I just tell them the CLD... |
Function cld() year=Right$(CurrentDate(),4) ny=year-2000;this means that it will work until 3000 A.D. (The world will collapse before then according to the signs..) ;2005 now = 5 ny=ny-1 ;compensate for the following year ;5 now = 4 ;2004=leapyear kip#=Float(ny/4) If kip# > ny And kip# < kip#+1 ;not leap year ly=False kip#=Left(kip#,1) ;now, add # of years dcld=365*ny dcld=dcld+kip# ;now, how many days this year month$=Mid(CurrentDate(),4,3) Select month$ Case "Jan" dcld=dcld+day Case "Feb" dcld=dcld+(31+day) Case "Mar" dcld=dcld+(31+28+day) Case "Apr" dcld=dcld+(31+28+31+day) Case "May" dcld=dcld+(31+28+31+30+day) Case "Jun" dcld=dcld+(31+28+31+30+31+day) Case "Jul" dcld=dcld+(31+28+31+30+31+30+day) Case "Aug" dcld=dcld+(31+28+31+30+31+30+31+day) Case "Sep" dcld=dcld+(31+28+31+30+31+30+31+31+day) Case "Oct" dcld=dcld+(31+28+31+30+31+30+31+31+30+day) Case "Nov" dcld=dcld+(31+28+31+30+31+30+31+31+30+31+day) Case "Dec" dcld=dcld+(31+28+31+30+31+30+31+31+30+31+30+day) End Select Else ;yup, its leap year ly=True kip#=Left(kip#,1) ;now, add # of years dcld=365*ny dcld=dcld+kip# ;now, how many days this year so far month$=Mid(CurrentDate(),4,3) Select month$ Case "Jan" dcld=dcld+day Case "Feb" dcld=dcld+(31+day) Case "Mar" dcld=dcld+(31+29+day) Case "Apr" dcld=dcld+(31+29+31+day) Case "May" dcld=dcld+(31+29+31+30+day) Case "Jun" dcld=dcld+(31+29+31+30+31+day) Case "Jul" dcld=dcld+(31+29+31+30+31+30+day) Case "Aug" dcld=dcld+(31+29+31+30+31+30+31+day) Case "Sep" dcld=dcld+(31+29+31+30+31+30+31+31+day) Case "Oct" dcld=dcld+(31+29+31+30+31+30+31+31+30+day) Case "Nov" dcld=dcld+(31+29+31+30+31+30+31+31+30+31+day) Case "Dec" dcld=dcld+(31+29+31+30+31+30+31+31+30+31+30+day) End Select EndIf Return dcld End Function |