equidistant point inside a spline

Hi !
i know how to draw a spline, but in my game i need equidistant points along the path ! Is there a formulae to do this ? i'm crap with math !
Thanks for your help

from my ingame code : spline

		For Local a:Float=0 To 1 - .01 Step .01    
			t.x[Index] = x1*(1-a)^3 + 3*vx1*(1-a)^2*a + 3*vx2*(1-a)*a^2 + x2*a^3
			t.y[Index] = y1*(1-a)^3 + 3*vy1*(1-a)^2*a + 3*vy2*(1-a)*a^2 + y2*a^3
			Index = Index + 1
		Next

Note that you can see the problem if you download my game, press f2 during the introscreen (cheat mode) and with the arrows keys choose level 10. (
http://www.bayre.com/zigwigwis/
to download click on 'telecharger')

As you draw the lines, count how many pixels are in the line, or work out how distant the points are apart, and split them if needed.?

Thanks

MyStep# = 0.0
a# = 0
index = 0
While a < 1
		  
a = a + MyStep
	
t.x[Index] = x1*(1-a)^3 + 3*vx1*(1-a)^2*a + 3*vx2*(1-a)*a^2 + x2*a^3
t.y[Index] = y1*(1-a)^3 + 3*vy1*(1-a)^2*a + 3*vy2*(1-a)*a^2 + y2*a^3
	
vx#= -3 * x1 * (1-a)^2 + 3 * vx1 * (1-a) * ((1-a)-2*a) + 3 * vx2 * a * (2*(1-a)-a) + x2 * 3 * a^2
vy#= -3 * y1 * (1-a)^2 + 3 * vy1 * (1-a) * ((1-a)-2*a) + 3 * vy2 * a * (2*(1-a)-a) + y2 * 3 * a^2
d#=Sqr(vx * vx + vy * vy)
MyStep# = Speed/d
Index = Index + 1
				
Wend

Thanks to Warpy :
http://www.blitzbasic.com/codearcs/codearcs.php?code=1523