IF and OR

Hi I'm wondering how I can construct an IF statement so that it is true if it equals one of two values given. For example

Local a:Int =8

DebugStop
If a = ( 6 Or 8 )
	Print "A is 6 or 8"
EndIf

I thought this would work but its obviously not evaluating what I would expect it to. Obviously I know I could put :
If ( a = 6 ) or ( a = 8 )

but I just wanted to make my code a little more readable as I have quite a few long if statements that are a little difficult to digest. Is this possible?
thanks

No this is not possible. Or is a binary operator that evaluates to {true,false}.
Your version would need some kind of list comparision.
You could get this behavior with

if not instr(["6","8"],string(a))

if I am not complete wrong

Ok thanks for your response

If your list is that much long and it really makes sense to shorten the test, you can just do

Select a Case 1,2,3,4,5
    Print "A is 1 or 2 or 3 or 4 or 5" 
End Select

If (a=6) or (a=8)

thats the one he didn't like ;-)

If you make the numbers more usefull like all the same mod value or with bitflagging, then you could the whole stuff really cut down to 1 test and 1 calculation in worst case.

Of course there's also:

Select a
case 1,2,3,4 Print "A is 1,2,3 or 4"
case 5 print "A is 5"
case 6,8 Print "A is 6 or 8"
end select

Which is a lot cleaner if you have to check for a whole bunch of conditions... But for just two or so, the if (a=6 or (a=8) is probably the easiest.