How pass an array to a function ?

how can i pass an multidimensional array in a function ?

example:

Global Pattern: Byte[7, 5]

function ModPattern: byte(aPattern[]: byte)
' ..... some code here ...
end function

Try

Function ModPattern(aPattern:Array)

Incidently, there's no compelling reason to pass something with Global visibility to a Function.

Well, if you also wanted to use locals as a parameter, there would be. Or you want to use it on multiple Global arrays.

Cam somebody expand on this for me please.
I want to pass 2 local arrays to the same function and return a single array
<edit>
Bit more info.
I'd like to put this into a function...

Local a[2]
Local b[2]
a[0]=0
a[1]=1
b[0]=2
b[1]=3
Local c[]
For n=EachIn a
   Print n
   Print "num : " + num
   c=c[..num+1]
   c[num]=n
   num:+1
Next  
For n=EachIn b
   Print "num : " + num
   c=c[..num+1]
   c[num]=n
   num:+1
Next  
For o = EachIn c
  Print o
Next 

I've tried using slices to copy the 2 arrays into a 3rd and also the listtoarray by creating a new list from the array list but without success.
If there's an easy way I have missed then please let me know.

Can't test it right now, but I would assume something like

Function myArrayThing:Array(array1:Array, array2:Array)

Should do the trick. At least if you're trying to do what I think you're trying to do.

Thanks for the quick response FlameDuck.
I have that as my function but I'm struggling on calling the function...
Local c:array[]=myArrayThing:array(a:array,b:array)
or many permutations of that.

To pass a (2d) array to a function, use something like:

Function ModPattern( aPattern:Byte[,] )
   'blah...
End Function

Local myPattern:Byte[10,10]

ModPattern myPattern

... and sending 2 single dimension arrays with a third array returned?

At home now, and this seems to be working:

Function myArrayThing:Array(array1[], array2[])

	Local result[array1.length + array2.length]
	Local c,i
	For i=EachIn array1
		result[c] = i
		c:+1
	Next

	For i=EachIn array2
		result[c] = i
		c:+1
	Next


	Return result
End Function

Local a:Int[] = [1,2,3,4]
Local b:Int[] = [5,6,7,8]
Local c:Int[] = myArrayThing(a,b)

For i=EachIn c
	Print i
Next

although I can't offer an explaination as to why Array <> [].

many many thanks. I'd tried so many things in so many permutations I'd lost the thread of what I was trying to do.
Thanks again.