Smarter compiler?

Is there a better way to do this ?

e#=1/2
DebugLog e# ;the compiler gives an integer result
Input ""
End

r1#=1
r2#=2
f#=r1#/r2#
DebugLog f# ;here the result is correct
Input ""
End

Should be:-

e#=1.0 / 2.0
DebugLog e# ;the compiler gives an integer result
Input ""
End

or

e#=Float#( 1 ) / Float#( 2 )
DebugLog e# ;the compiler gives an integer result
Input ""
End

Thanks!

what it does, because the values passed are integer, is work out 1/2 and gives the result as an integer which is then given to e#, even though it is a float the value given is rounded.

@sinu: ja, that I knew. But that isn't how most compilers work. :)