I need ur help for floating :)

Hi all,

Am looking for an little rutime, but i have float like :
89.8899887 and i wan to have only 89.88

If someone have an function for kick the extra...

Many thanks
Stephanie

hmm. How's this:

Print floater#(89.8899887,2)

Function floater#(Flot#,num)
 num=10^num
 Return Float(Floor(Flot#*num))/num
End Function

Woot many thanks BOT !

Kiss ya
Stephanie